Whakaoti i te x^2+3x+9=(x+2)^2-17

$$x ^ { 2 } + 3 x + 9 = ( x + 2 ) ^ { 2 } - 17$$

Whakaoti mō x

$$x=22$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+2\right)^{2}.

$$x^{2}+3x+9=x^{2}+4x+4-17$$

Tangohia te 17 i te 4, ka -13.

$$x^{2}+3x+9=x^{2}+4x-13$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+3x+9-x^{2}=4x-13$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$3x+9=4x-13$$

Tangohia te 4x mai i ngā taha e rua.

$$3x+9-4x=-13$$

Pahekotia te 3x me -4x, ka -x.

$$-x+9=-13$$

Tangohia te 9 mai i ngā taha e rua.

$$-x=-13-9$$

Tangohia te 9 i te -13, ka -22.

$$-x=-22$$

Me whakarea ngā taha e rua ki te -1.

$$x=22$$