Whakaoti i te x^2+3x+8=(x+2)^2-19

$$x ^ { 2 } + 3 x + 8 = ( x + 2 ) ^ { 2 } - 19$$

Whakaoti mō x

$$x=23$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+2\right)^{2}.

$$x^{2}+3x+8=x^{2}+4x+4-19$$

Tangohia te 19 i te 4, ka -15.

$$x^{2}+3x+8=x^{2}+4x-15$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+3x+8-x^{2}=4x-15$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$3x+8=4x-15$$

Tangohia te 4x mai i ngā taha e rua.

$$3x+8-4x=-15$$

Pahekotia te 3x me -4x, ka -x.

$$-x+8=-15$$

Tangohia te 8 mai i ngā taha e rua.

$$-x=-15-8$$

Tangohia te 8 i te -15, ka -23.

$$-x=-23$$

Me whakarea ngā taha e rua ki te -1.

$$x=23$$