Whakaoti i te x^2+2x-4

$$x ^ { 2 } + 2 x - 4$$

Tauwehe

$$\left(x-\left(-\sqrt{5}-1\right)\right)\left(x-\left(\sqrt{5}-1\right)\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$x^{2}+2x-4=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-2±\sqrt{2^{2}-4\left(-4\right)}}{2}$$

Pūrua 2.

$$x=\frac{-2±\sqrt{4-4\left(-4\right)}}{2}$$

Whakareatia -4 ki te -4.

$$x=\frac{-2±\sqrt{4+16}}{2}$$

Tāpiri 4 ki te 16.

$$x=\frac{-2±\sqrt{20}}{2}$$

Tuhia te pūtakerua o te 20.

$$x=\frac{-2±2\sqrt{5}}{2}$$

Nā, me whakaoti te whārite x=\frac{-2±2\sqrt{5}}{2} ina he tāpiri te ±. Tāpiri -2 ki te 2\sqrt{5}.

$$x=\frac{2\sqrt{5}-2}{2}$$

Whakawehe -2+2\sqrt{5} ki te 2.

$$x=\sqrt{5}-1$$

Nā, me whakaoti te whārite x=\frac{-2±2\sqrt{5}}{2} ina he tango te ±. Tango 2\sqrt{5} mai i -2.

$$x=\frac{-2\sqrt{5}-2}{2}$$

Whakawehe -2-2\sqrt{5} ki te 2.

$$x=-\sqrt{5}-1$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te -1+\sqrt{5} mō te x_{1} me te -1-\sqrt{5} mō te x_{2}.

$$x^{2}+2x-4=\left(x-\left(\sqrt{5}-1\right)\right)\left(x-\left(-\sqrt{5}-1\right)\right)$$

Aromātai

$$x^{2}+2x-4$$