Whakaoti i te x^2+2x-3x^2+x-2x^2-1

$$x ^ { 2 } + 2 x - 3 x ^ { 2 } + x - 2 x ^ { 2 } - 1$$

Aromātai

$$-4x^{2}+3x-1$$

Ngā Upane Otinga

Pahekotia te x^{2} me -3x^{2}, ka -2x^{2}.

$$-2x^{2}+2x+x-2x^{2}-1$$

Pahekotia te 2x me x, ka 3x.

$$-2x^{2}+3x-2x^{2}-1$$

Pahekotia te -2x^{2} me -2x^{2}, ka -4x^{2}.

$$-4x^{2}+3x-1$$

Kimi Pārōnaki e ai ki x

$$3-8x$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te x^{2} me -3x^{2}, ka -2x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-2x^{2}+2x+x-2x^{2}-1)$$

Pahekotia te 2x me x, ka 3x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-2x^{2}+3x-2x^{2}-1)$$

Pahekotia te -2x^{2} me -2x^{2}, ka -4x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-4x^{2}+3x-1)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\left(-4\right)x^{2-1}+3x^{1-1}$$

Whakareatia 2 ki te -4.

$$-8x^{2-1}+3x^{1-1}$$

Tango 1 mai i 2.

$$-8x^{1}+3x^{1-1}$$

Tango 1 mai i 1.

$$-8x^{1}+3x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$-8x+3x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$-8x+3\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$-8x+3$$