Whakaoti i te x^2+2=10

$$x ^ { 2 } + 2 = 10$$

Whakaoti mō x

$$x=2\sqrt{2}\approx 2.828427125$$

$$x=-2\sqrt{2}\approx -2.828427125$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 2 mai i ngā taha e rua.

$$x^{2}=10-2$$

Tangohia te 2 i te 10, ka 8.

$$x^{2}=8$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=2\sqrt{2} x=-2\sqrt{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 10 mai i ngā taha e rua.

$$x^{2}+2-10=0$$

Tangohia te 10 i te 2, ka -8.

$$x^{2}-8=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -8 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-8\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-8\right)}}{2}$$

Whakareatia -4 ki te -8.

$$x=\frac{0±\sqrt{32}}{2}$$

Tuhia te pūtakerua o te 32.

$$x=\frac{0±4\sqrt{2}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{2}}{2} ina he tāpiri te ±.

$$x=2\sqrt{2}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{2}}{2} ina he tango te ±.

$$x=-2\sqrt{2}$$

Kua oti te whārite te whakatau.

$$x=2\sqrt{2} x=-2\sqrt{2}$$