Whakaoti i te x^2+2=1

$$x ^ { 2 } + 2 = 1$$

Whakaoti mō x (complex solution)

$$x=-i$$

$$x=i$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 2 mai i ngā taha e rua.

$$x^{2}=1-2$$

Tangohia te 2 i te 1, ka -1.

$$x^{2}=-1$$

Kua oti te whārite te whakatau.

$$x=i x=-i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$x^{2}+2-1=0$$

Tangohia te 1 i te 2, ka 1.

$$x^{2}+1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4}}{2}$$

Tuhia te pūtakerua o te -4.

$$x=\frac{0±2i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2i}{2} ina he tāpiri te ±.

$$x=i$$

Nā, me whakaoti te whārite x=\frac{0±2i}{2} ina he tango te ±.

$$x=-i$$

Kua oti te whārite te whakatau.

$$x=i x=-i$$