Whakaoti i te x^2+2=0

$$x ^ { 2 } + 2 = 0$$

Whakaoti mō x (complex solution)

$$x=-\sqrt{2}i\approx -0-1.414213562i$$

$$x=\sqrt{2}i\approx 1.414213562i$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 2 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$x^{2}=-2$$

Kua oti te whārite te whakatau.

$$x=\sqrt{2}i x=-\sqrt{2}i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$x^{2}+2=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me 2 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 2}}{2}$$

Whakareatia -4 ki te 2.

$$x=\frac{0±\sqrt{-8}}{2}$$

Tuhia te pūtakerua o te -8.

$$x=\frac{0±2\sqrt{2}i}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2}i}{2} ina he tāpiri te ±.

$$x=\sqrt{2}i$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2}i}{2} ina he tango te ±.

$$x=-\sqrt{2}i$$

Kua oti te whārite te whakatau.

$$x=\sqrt{2}i x=-\sqrt{2}i$$