Whakaoti i te x^2+17x-60

$$x ^ { 2 } + 17 x - 60$$

Tauwehe

$$\left(x-3\right)\left(x+20\right)$$

Ngā Upane Otinga

Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei x^{2}+ax+bx-60. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=17 ab=1\left(-60\right)=-60$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōrunga te a+b, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -60.

$$-1,60 -2,30 -3,20 -4,15 -5,12 -6,10$$

Tātaihia te tapeke mō ia takirua.

$$-1+60=59 -2+30=28 -3+20=17 -4+15=11 -5+12=7 -6+10=4$$

Ko te otinga te takirua ka hoatu i te tapeke 17.

$$a=-3 b=20$$

Tuhia anō te x^{2}+17x-60 hei \left(x^{2}-3x\right)+\left(20x-60\right).

$$\left(x^{2}-3x\right)+\left(20x-60\right)$$

Tauwehea te x i te tuatahi me te 20 i te rōpū tuarua.

$$x\left(x-3\right)+20\left(x-3\right)$$

Whakatauwehea atu te kīanga pātahi x-3 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-3\right)\left(x+20\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$x^{2}+17x-60=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-17±\sqrt{17^{2}-4\left(-60\right)}}{2}$$

Pūrua 17.

$$x=\frac{-17±\sqrt{289-4\left(-60\right)}}{2}$$

Whakareatia -4 ki te -60.

$$x=\frac{-17±\sqrt{289+240}}{2}$$

Tāpiri 289 ki te 240.

$$x=\frac{-17±\sqrt{529}}{2}$$

Tuhia te pūtakerua o te 529.

$$x=\frac{-17±23}{2}$$

Nā, me whakaoti te whārite x=\frac{-17±23}{2} ina he tāpiri te ±. Tāpiri -17 ki te 23.

$$x=\frac{6}{2}$$

Whakawehe 6 ki te 2.

$$x=3$$

Nā, me whakaoti te whārite x=\frac{-17±23}{2} ina he tango te ±. Tango 23 mai i -17.

$$x=-\frac{40}{2}$$

Whakawehe -40 ki te 2.

$$x=-20$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 3 mō te x_{1} me te -20 mō te x_{2}.

$$x^{2}+17x-60=\left(x-3\right)\left(x-\left(-20\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$x^{2}+17x-60=\left(x-3\right)\left(x+20\right)$$

Aromātai

$$\left(x-3\right)\left(x+20\right)$$