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Whakaoti mō x (complex solution)
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Whakaoti mō x
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x^{2}+10x-21=0
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
x=\frac{-10±\sqrt{10^{2}-4\left(-21\right)}}{2}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 10 mō b, me -21 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-10±\sqrt{100-4\left(-21\right)}}{2}
Pūrua 10.
x=\frac{-10±\sqrt{100+84}}{2}
Whakareatia -4 ki te -21.
x=\frac{-10±\sqrt{184}}{2}
Tāpiri 100 ki te 84.
x=\frac{-10±2\sqrt{46}}{2}
Tuhia te pūtakerua o te 184.
x=\frac{2\sqrt{46}-10}{2}
Nā, me whakaoti te whārite x=\frac{-10±2\sqrt{46}}{2} ina he tāpiri te ±. Tāpiri -10 ki te 2\sqrt{46}.
x=\sqrt{46}-5
Whakawehe -10+2\sqrt{46} ki te 2.
x=\frac{-2\sqrt{46}-10}{2}
Nā, me whakaoti te whārite x=\frac{-10±2\sqrt{46}}{2} ina he tango te ±. Tango 2\sqrt{46} mai i -10.
x=-\sqrt{46}-5
Whakawehe -10-2\sqrt{46} ki te 2.
x=\sqrt{46}-5 x=-\sqrt{46}-5
Kua oti te whārite te whakatau.
x^{2}+10x-21=0
Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.
x^{2}+10x-21-\left(-21\right)=-\left(-21\right)
Me tāpiri 21 ki ngā taha e rua o te whārite.
x^{2}+10x=-\left(-21\right)
Mā te tango i te -21 i a ia ake anō ka toe ko te 0.
x^{2}+10x=21
Tango -21 mai i 0.
x^{2}+10x+5^{2}=21+5^{2}
Whakawehea te 10, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te 5. Nā, tāpiria te pūrua o te 5 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.
x^{2}+10x+25=21+25
Pūrua 5.
x^{2}+10x+25=46
Tāpiri 21 ki te 25.
\left(x+5\right)^{2}=46
Tauwehea x^{2}+10x+25. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+5\right)^{2}}=\sqrt{46}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
x+5=\sqrt{46} x+5=-\sqrt{46}
Whakarūnātia.
x=\sqrt{46}-5 x=-\sqrt{46}-5
Me tango 5 mai i ngā taha e rua o te whārite.
x^{2}+10x-21=0
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
x=\frac{-10±\sqrt{10^{2}-4\left(-21\right)}}{2}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 10 mō b, me -21 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-10±\sqrt{100-4\left(-21\right)}}{2}
Pūrua 10.
x=\frac{-10±\sqrt{100+84}}{2}
Whakareatia -4 ki te -21.
x=\frac{-10±\sqrt{184}}{2}
Tāpiri 100 ki te 84.
x=\frac{-10±2\sqrt{46}}{2}
Tuhia te pūtakerua o te 184.
x=\frac{2\sqrt{46}-10}{2}
Nā, me whakaoti te whārite x=\frac{-10±2\sqrt{46}}{2} ina he tāpiri te ±. Tāpiri -10 ki te 2\sqrt{46}.
x=\sqrt{46}-5
Whakawehe -10+2\sqrt{46} ki te 2.
x=\frac{-2\sqrt{46}-10}{2}
Nā, me whakaoti te whārite x=\frac{-10±2\sqrt{46}}{2} ina he tango te ±. Tango 2\sqrt{46} mai i -10.
x=-\sqrt{46}-5
Whakawehe -10-2\sqrt{46} ki te 2.
x=\sqrt{46}-5 x=-\sqrt{46}-5
Kua oti te whārite te whakatau.
x^{2}+10x-21=0
Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.
x^{2}+10x-21-\left(-21\right)=-\left(-21\right)
Me tāpiri 21 ki ngā taha e rua o te whārite.
x^{2}+10x=-\left(-21\right)
Mā te tango i te -21 i a ia ake anō ka toe ko te 0.
x^{2}+10x=21
Tango -21 mai i 0.
x^{2}+10x+5^{2}=21+5^{2}
Whakawehea te 10, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te 5. Nā, tāpiria te pūrua o te 5 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.
x^{2}+10x+25=21+25
Pūrua 5.
x^{2}+10x+25=46
Tāpiri 21 ki te 25.
\left(x+5\right)^{2}=46
Tauwehea x^{2}+10x+25. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+5\right)^{2}}=\sqrt{46}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
x+5=\sqrt{46} x+5=-\sqrt{46}
Whakarūnātia.
x=\sqrt{46}-5 x=-\sqrt{46}-5
Me tango 5 mai i ngā taha e rua o te whārite.