Whakaoti i te x^2+1=164

$$x ^ { 2 } + 1 = 164$$

Whakaoti mō x

$$x=\sqrt{163}\approx 12.767145335$$

$$x=-\sqrt{163}\approx -12.767145335$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 1 mai i ngā taha e rua.

$$x^{2}=164-1$$

Tangohia te 1 i te 164, ka 163.

$$x^{2}=163$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{163} x=-\sqrt{163}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 164 mai i ngā taha e rua.

$$x^{2}+1-164=0$$

Tangohia te 164 i te 1, ka -163.

$$x^{2}-163=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -163 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-163\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-163\right)}}{2}$$

Whakareatia -4 ki te -163.

$$x=\frac{0±\sqrt{652}}{2}$$

Tuhia te pūtakerua o te 652.

$$x=\frac{0±2\sqrt{163}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{163}}{2} ina he tāpiri te ±.

$$x=\sqrt{163}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{163}}{2} ina he tango te ±.

$$x=-\sqrt{163}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{163} x=-\sqrt{163}$$