Whakaoti i te x^2+1/25=1

$$x ^ { 2 } + \frac { 1 } { 25 } = 1$$

Whakaoti mō x

$$x=\frac{2\sqrt{6}}{5}\approx 0.979795897$$

$$x=-\frac{2\sqrt{6}}{5}\approx -0.979795897$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te \frac{1}{25} mai i ngā taha e rua.

$$x^{2}=1-\frac{1}{25}$$

Tangohia te \frac{1}{25} i te 1, ka \frac{24}{25}.

$$x^{2}=\frac{24}{25}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{2\sqrt{6}}{5} x=-\frac{2\sqrt{6}}{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 1 mai i ngā taha e rua.

$$x^{2}+\frac{1}{25}-1=0$$

Tangohia te 1 i te \frac{1}{25}, ka -\frac{24}{25}.

$$x^{2}-\frac{24}{25}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -\frac{24}{25} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{24}{25}\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{24}{25}\right)}}{2}$$

Whakareatia -4 ki te -\frac{24}{25}.

$$x=\frac{0±\sqrt{\frac{96}{25}}}{2}$$

Tuhia te pūtakerua o te \frac{96}{25}.

$$x=\frac{0±\frac{4\sqrt{6}}{5}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{4\sqrt{6}}{5}}{2} ina he tāpiri te ±.

$$x=\frac{2\sqrt{6}}{5}$$

Nā, me whakaoti te whārite x=\frac{0±\frac{4\sqrt{6}}{5}}{2} ina he tango te ±.

$$x=-\frac{2\sqrt{6}}{5}$$

Kua oti te whārite te whakatau.

$$x=\frac{2\sqrt{6}}{5} x=-\frac{2\sqrt{6}}{5}$$