Whakaoti i te x^16-1

$$x ^ { 16 } - 1$$

Tauwehe

$$\left(x-1\right)\left(x+1\right)\left(x^{2}+1\right)\left(x^{4}+1\right)\left(x^{8}+1\right)$$

Ngā Upane Otinga

Tuhia anō te x^{16}-1 hei \left(x^{8}\right)^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x^{8}-1\right)\left(x^{8}+1\right)$$

Whakaarohia te x^{8}-1. Tuhia anō te x^{8}-1 hei \left(x^{4}\right)^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x^{4}-1\right)\left(x^{4}+1\right)$$

Whakaarohia te x^{4}-1. Tuhia anō te x^{4}-1 hei \left(x^{2}\right)^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x^{2}-1\right)\left(x^{2}+1\right)$$

Whakaarohia te x^{2}-1. Tuhia anō te x^{2}-1 hei x^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-1\right)\left(x+1\right)$$

Me tuhi anō te kīanga whakatauwehe katoa. Kāore i tauwehea ēnei pūrau i te mea kāhore ō rātou pūtake whakahau: x^{2}+1,x^{4}+1,x^{8}+1.

$$\left(x-1\right)\left(x+1\right)\left(x^{2}+1\right)\left(x^{4}+1\right)\left(x^{8}+1\right)$$

Aromātai

$$x^{16}-1$$