Whakaoti i te x^-3=(1/x)^3

$$x ^ { - 3 } = ( \frac { 1 } { x } ) ^ { 3 }$$

Whakaoti mō x

$$x\neq 0$$

Ngā Hipanga Rongoā Poto

Kia whakarewa i te \frac{1}{x} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$x^{-3}=\frac{1^{3}}{x^{3}}$$

Tātaihia te 1 mā te pū o 3, kia riro ko 1.

$$x^{-3}=\frac{1}{x^{3}}$$

Tangohia te \frac{1}{x^{3}} mai i ngā taha e rua.

$$x^{-3}-\frac{1}{x^{3}}=0$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x^{-3} ki te \frac{x^{3}}{x^{3}}.

$$\frac{x^{-3}x^{3}}{x^{3}}-\frac{1}{x^{3}}=0$$

Tā te mea he rite te tauraro o \frac{x^{-3}x^{3}}{x^{3}} me \frac{1}{x^{3}}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{x^{-3}x^{3}-1}{x^{3}}=0$$

Mahia ngā whakarea i roto o x^{-3}x^{3}-1.

$$\frac{1-1}{x^{3}}=0$$

Mahia ngā tātaitai i roto o 1-1.

$$\frac{0}{x^{3}}=0$$

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x^{3}.

$$0=0$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{R}$$

Tē taea kia ōrite te tāupe x ki 0.

$$x\in \mathrm{R}\setminus 0$$