Whakaoti i te x=d+ydx/y

$$x = d + y \frac { d x } { y }$$

Whakaoti mō d

$$d=\frac{x}{x+1}$$

$$x\neq -1\text{ and }y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te y.

$$xy=yd+ydx$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$yd+ydx=xy$$

Pahekotia ngā kīanga tau katoa e whai ana i te d.

$$\left(y+yx\right)d=xy$$

He hanga arowhānui tō te whārite.

$$\left(xy+y\right)d=xy$$

Whakawehea ngā taha e rua ki te y+yx.

$$\frac{\left(xy+y\right)d}{xy+y}=\frac{xy}{xy+y}$$

Mā te whakawehe ki te y+yx ka wetekia te whakareanga ki te y+yx.

$$d=\frac{xy}{xy+y}$$

Whakawehe xy ki te y+yx.

$$d=\frac{x}{x+1}$$

Whakaoti mō x

$$x=\frac{d}{1-d}$$

$$d\neq 1\text{ and }y\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tuhia te y\times \frac{dx}{y} hei hautanga kotahi.

$$x=d+\frac{ydx}{y}$$

Me whakakore tahi te y i te taurunga me te tauraro.

$$x=d+dx$$

Tangohia te dx mai i ngā taha e rua.

$$x-dx=d$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(1-d\right)x=d$$

Whakawehea ngā taha e rua ki te 1-d.

$$\frac{\left(1-d\right)x}{1-d}=\frac{d}{1-d}$$

Mā te whakawehe ki te 1-d ka wetekia te whakareanga ki te 1-d.

$$x=\frac{d}{1-d}$$