Whakaoti i te x=-1/y-1+3/4

$$x = - \frac { 1 } { y - 1 } + \frac { 3 } { 4 }$$

Whakaoti mō y

$$y=-\frac{7-4x}{4x-3}$$

$$x\neq \frac{3}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe y ki 1 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te 4\left(y-1\right), arā, te tauraro pātahi he tino iti rawa te kitea o y-1,4.

$$x\times 4\left(y-1\right)=-4+4\left(y-1\right)\times \frac{3}{4}$$

Whakamahia te āhuatanga tohatoha hei whakarea te x\times 4 ki te y-1.

$$4xy-x\times 4=-4+4\left(y-1\right)\times \frac{3}{4}$$

Whakareatia te -1 ki te 4, ka -4.

$$4xy-4x=-4+4\left(y-1\right)\times \frac{3}{4}$$

Whakareatia te 4 ki te \frac{3}{4}, ka 3.

$$4xy-4x=-4+3\left(y-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te y-1.

$$4xy-4x=-4+3y-3$$

Tangohia te 3 i te -4, ka -7.

$$4xy-4x=-7+3y$$

Tangohia te 3y mai i ngā taha e rua.

$$4xy-4x-3y=-7$$

Me tāpiri te 4x ki ngā taha e rua.

$$4xy-3y=-7+4x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(4x-3\right)y=-7+4x$$

He hanga arowhānui tō te whārite.

$$\left(4x-3\right)y=4x-7$$

Whakawehea ngā taha e rua ki te 4x-3.

$$\frac{\left(4x-3\right)y}{4x-3}=\frac{4x-7}{4x-3}$$

Mā te whakawehe ki te 4x-3 ka wetekia te whakareanga ki te 4x-3.

$$y=\frac{4x-7}{4x-3}$$

Tē taea kia ōrite te tāupe y ki 1.

$$y=\frac{4x-7}{4x-3}\text{, }y\neq 1$$

Whakaoti mō x

$$x=-\frac{7-3y}{4\left(y-1\right)}$$

$$y\neq 1$$