Whakaoti i te x=sqrt{x}*x+x/x

$$x = \sqrt { x } \times \frac { x + x } { x }$$

Whakaoti mō x

$$x=4$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$x^{2}=\left(\sqrt{x}\times \frac{x+x}{x}\right)^{2}$$

Pahekotia te x me x, ka 2x.

$$x^{2}=\left(\sqrt{x}\times \frac{2x}{x}\right)^{2}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$x^{2}=\left(\sqrt{x}\times 2\right)^{2}$$

Whakarohaina te \left(\sqrt{x}\times 2\right)^{2}.

$$x^{2}=\left(\sqrt{x}\right)^{2}\times 2^{2}$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$x^{2}=x\times 2^{2}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$x^{2}=x\times 4$$

Tangohia te x\times 4 mai i ngā taha e rua.

$$x^{2}-x\times 4=0$$

Whakareatia te -1 ki te 4, ka -4.

$$x^{2}-4x=0$$

Tauwehea te x.

$$x\left(x-4\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te x-4=0.

$$x=0 x=4$$

Whakakapia te 0 mō te x i te whārite x=\sqrt{x}\times \frac{x+x}{x}. Kāore e tautuhia e te kīanga.

$$0=\sqrt{0}\times \frac{0+0}{0}$$

Whakakapia te 4 mō te x i te whārite x=\sqrt{x}\times \frac{x+x}{x}.

$$4=\sqrt{4}\times \frac{4+4}{4}$$

Whakarūnātia. Ko te uara x=4 kua ngata te whārite.

$$4=4$$

Ko te whārite x=\frac{x+x}{x}\sqrt{x} he rongoā ahurei.

$$x=4$$