Whakaoti i te x=sqrt{4-x^2}

$$x = \sqrt { 4 - x ^ { 2 } }$$

Whakaoti mō x

$$x=\sqrt{2}\approx 1.414213562$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$x^{2}=\left(\sqrt{4-x^{2}}\right)^{2}$$

Tātaihia te \sqrt{4-x^{2}} mā te pū o 2, kia riro ko 4-x^{2}.

$$x^{2}=4-x^{2}$$

Me tāpiri te x^{2} ki ngā taha e rua.

$$x^{2}+x^{2}=4$$

Pahekotia te x^{2} me x^{2}, ka 2x^{2}.

$$2x^{2}=4$$

Whakawehea ngā taha e rua ki te 2.

$$x^{2}=\frac{4}{2}$$

Whakawehea te 4 ki te 2, kia riro ko 2.

$$x^{2}=2$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{2} x=-\sqrt{2}$$

Whakakapia te \sqrt{2} mō te x i te whārite x=\sqrt{4-x^{2}}.

$$\sqrt{2}=\sqrt{4-\left(\sqrt{2}\right)^{2}}$$

Whakarūnātia. Ko te uara x=\sqrt{2} kua ngata te whārite.

$$2^{\frac{1}{2}}=2^{\frac{1}{2}}$$

Whakakapia te -\sqrt{2} mō te x i te whārite x=\sqrt{4-x^{2}}.

$$-\sqrt{2}=\sqrt{4-\left(-\sqrt{2}\right)^{2}}$$

Whakarūnātia. Ko te uara x=-\sqrt{2} kāore e ngata ana ki te whārite nā te mea e rerekē ngā tohu o te taha maui me te taha katau.

$$-2^{\frac{1}{2}}=2^{\frac{1}{2}}$$

Ko te whārite x=\sqrt{4-x^{2}} he rongoā ahurei.

$$x=\sqrt{2}$$