Whakaoti i te x=a/5x+32

$$x = \frac { a } { 5 } x + 32$$

Whakaoti mō a

$$a=5-\frac{160}{x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tuhia te \frac{a}{5}x hei hautanga kotahi.

$$x=\frac{ax}{5}+32$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{ax}{5}+32=x$$

Tangohia te 32 mai i ngā taha e rua.

$$\frac{ax}{5}=x-32$$

Whakareatia ngā taha e rua o te whārite ki te 5.

$$ax=5x-160$$

He hanga arowhānui tō te whārite.

$$xa=5x-160$$

Whakawehea ngā taha e rua ki te x.

$$\frac{xa}{x}=\frac{5x-160}{x}$$

Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.

$$a=\frac{5x-160}{x}$$

Whakawehe -160+5x ki te x.

$$a=5-\frac{160}{x}$$

Whakaoti mō x

$$x=\frac{160}{5-a}$$

$$a\neq 5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tuhia te \frac{a}{5}x hei hautanga kotahi.

$$x=\frac{ax}{5}+32$$

Tangohia te \frac{ax}{5} mai i ngā taha e rua.

$$x-\frac{ax}{5}=32$$

Whakareatia ngā taha e rua o te whārite ki te 5.

$$5x-ax=160$$

Whakaraupapatia anō ngā kīanga tau.

$$-ax+5x=160$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(-a+5\right)x=160$$

He hanga arowhānui tō te whārite.

$$\left(5-a\right)x=160$$

Whakawehea ngā taha e rua ki te -a+5.

$$\frac{\left(5-a\right)x}{5-a}=\frac{160}{5-a}$$

Mā te whakawehe ki te -a+5 ka wetekia te whakareanga ki te -a+5.

$$x=\frac{160}{5-a}$$