Whakaoti i te x=4y-1/2y+3

$$x = \frac { 4 y - 1 } { 2 y + 3 }$$

Whakaoti mō y

$$y=-\frac{3x+1}{2\left(x-2\right)}$$

$$x\neq 2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe y ki -\frac{3}{2} nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te 2y+3.

$$x\left(2y+3\right)=4y-1$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te 2y+3.

$$2xy+3x=4y-1$$

Tangohia te 4y mai i ngā taha e rua.

$$2xy+3x-4y=-1$$

Tangohia te 3x mai i ngā taha e rua.

$$2xy-4y=-1-3x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(2x-4\right)y=-1-3x$$

He hanga arowhānui tō te whārite.

$$\left(2x-4\right)y=-3x-1$$

Whakawehea ngā taha e rua ki te 2x-4.

$$\frac{\left(2x-4\right)y}{2x-4}=\frac{-3x-1}{2x-4}$$

Mā te whakawehe ki te 2x-4 ka wetekia te whakareanga ki te 2x-4.

$$y=\frac{-3x-1}{2x-4}$$

Whakawehe -1-3x ki te 2x-4.

$$y=-\frac{3x+1}{2\left(x-2\right)}$$

Tē taea kia ōrite te tāupe y ki -\frac{3}{2}.

$$y=-\frac{3x+1}{2\left(x-2\right)}\text{, }y\neq -\frac{3}{2}$$

Whakaoti mō x

$$x=-\frac{1-4y}{2y+3}$$

$$y\neq -\frac{3}{2}$$