Whakaoti i te x=1/2^2+1/y

$$x = \frac{ 1 }{ { 2 }^{ 2 } } + \frac{ 1 }{ y }$$

Whakaoti mō y

$$y=-\frac{4}{1-4x}$$

$$x\neq \frac{1}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe y ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te y.

$$xy=\frac{1}{4}y+1$$

Tangohia te \frac{1}{4}y mai i ngā taha e rua.

$$xy-\frac{1}{4}y=1$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(x-\frac{1}{4}\right)y=1$$

Whakawehea ngā taha e rua ki te x-\frac{1}{4}.

$$\frac{\left(x-\frac{1}{4}\right)y}{x-\frac{1}{4}}=\frac{1}{x-\frac{1}{4}}$$

Mā te whakawehe ki te x-\frac{1}{4} ka wetekia te whakareanga ki te x-\frac{1}{4}.

$$y=\frac{1}{x-\frac{1}{4}}$$

Whakawehe 1 ki te x-\frac{1}{4}.

$$y=\frac{4}{4x-1}$$

Tē taea kia ōrite te tāupe y ki 0.

$$y=\frac{4}{4x-1}\text{, }y\neq 0$$

Whakaoti mō x

$$x=\frac{1}{4}+\frac{1}{y}$$

$$y\neq 0$$