Whakaoti i te x+1-4/x+1=x-1

$$x + 1 - \frac { 4 } { x + 1 } = x - 1$$

Whakaoti mō x

$$x=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki -1 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x+1.

$$\left(x+1\right)x+x+1-4=\left(x+1\right)x+\left(x+1\right)\left(-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te x.

$$x^{2}+x+x+1-4=\left(x+1\right)x+\left(x+1\right)\left(-1\right)$$

Pahekotia te x me x, ka 2x.

$$x^{2}+2x+1-4=\left(x+1\right)x+\left(x+1\right)\left(-1\right)$$

Tangohia te 4 i te 1, ka -3.

$$x^{2}+2x-3=\left(x+1\right)x+\left(x+1\right)\left(-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te x.

$$x^{2}+2x-3=x^{2}+x+\left(x+1\right)\left(-1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x+1 ki te -1.

$$x^{2}+2x-3=x^{2}+x-x-1$$

Pahekotia te x me -x, ka 0.

$$x^{2}+2x-3=x^{2}-1$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+2x-3-x^{2}=-1$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$2x-3=-1$$

Me tāpiri te 3 ki ngā taha e rua.

$$2x=-1+3$$

Tāpirihia te -1 ki te 3, ka 2.

$$2x=2$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{2}{2}$$

Whakawehea te 2 ki te 2, kia riro ko 1.

$$x=1$$