Whakaoti i te x+1+3x/x^2-x-6

$$x + 1 + \frac { 3 x } { x ^ { 2 } - x - 6 }$$

Aromātai

$$\frac{x^{3}-4x-6}{\left(x-3\right)\left(x+2\right)}$$

Ngā Hipanga Rongoā Poto

Tauwehea te x^{2}-x-6.

$$x+1+\frac{3x}{\left(x-3\right)\left(x+2\right)}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia x+1 ki te \frac{\left(x-3\right)\left(x+2\right)}{\left(x-3\right)\left(x+2\right)}.

$$\frac{\left(x+1\right)\left(x-3\right)\left(x+2\right)}{\left(x-3\right)\left(x+2\right)}+\frac{3x}{\left(x-3\right)\left(x+2\right)}$$

Tā te mea he rite te tauraro o \frac{\left(x+1\right)\left(x-3\right)\left(x+2\right)}{\left(x-3\right)\left(x+2\right)} me \frac{3x}{\left(x-3\right)\left(x+2\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{\left(x+1\right)\left(x-3\right)\left(x+2\right)+3x}{\left(x-3\right)\left(x+2\right)}$$

Mahia ngā whakarea i roto o \left(x+1\right)\left(x-3\right)\left(x+2\right)+3x.

$$\frac{x^{3}-x^{2}-6x+x^{2}-x-6+3x}{\left(x-3\right)\left(x+2\right)}$$

Whakakotahitia ngā kupu rite i x^{3}-x^{2}-6x+x^{2}-x-6+3x.

$$\frac{x^{3}-4x-6}{\left(x-3\right)\left(x+2\right)}$$

Whakarohaina te \left(x-3\right)\left(x+2\right).

$$\frac{x^{3}-4x-6}{x^{2}-x-6}$$

Kimi Pārōnaki e ai ki x

$$\frac{x^{4}-2x^{3}-14x^{2}+12x+18}{\left(\left(x-3\right)\left(x+2\right)\right)^{2}}$$