Whakaoti i te x+6/2=10/4

$$x + \frac { 6 } { 2 } = \frac { 10 } { 4 }$$

Whakaoti mō x

$$x=-\frac{1}{2}=-0.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawehea te 6 ki te 2, kia riro ko 3.

$$x+3=\frac{10}{4}$$

Whakahekea te hautanga \frac{10}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x+3=\frac{5}{2}$$

Tangohia te 3 mai i ngā taha e rua.

$$x=\frac{5}{2}-3$$

Me tahuri te 3 ki te hautau \frac{6}{2}.

$$x=\frac{5}{2}-\frac{6}{2}$$

Tā te mea he rite te tauraro o \frac{5}{2} me \frac{6}{2}, me tango rāua mā te tango i ō raua taurunga.

$$x=\frac{5-6}{2}$$

Tangohia te 6 i te 5, ka -1.

$$x=-\frac{1}{2}$$