Whakaoti i te x+2/3-1/2=17/18

$$x + \frac { 2 } { 3 } - \frac { 1 } { 2 } = \frac { 17 } { 18 }$$

Whakaoti mō x

$$x=\frac{7}{9}\approx 0.777777778$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Ko te maha noa iti rawa atu o 3 me 2 ko 6. Me tahuri \frac{2}{3} me \frac{1}{2} ki te hautau me te tautūnga 6.

$$x+\frac{4}{6}-\frac{3}{6}=\frac{17}{18}$$

Tā te mea he rite te tauraro o \frac{4}{6} me \frac{3}{6}, me tango rāua mā te tango i ō raua taurunga.

$$x+\frac{4-3}{6}=\frac{17}{18}$$

Tangohia te 3 i te 4, ka 1.

$$x+\frac{1}{6}=\frac{17}{18}$$

Tangohia te \frac{1}{6} mai i ngā taha e rua.

$$x=\frac{17}{18}-\frac{1}{6}$$

Ko te maha noa iti rawa atu o 18 me 6 ko 18. Me tahuri \frac{17}{18} me \frac{1}{6} ki te hautau me te tautūnga 18.

$$x=\frac{17}{18}-\frac{3}{18}$$

Tā te mea he rite te tauraro o \frac{17}{18} me \frac{3}{18}, me tango rāua mā te tango i ō raua taurunga.

$$x=\frac{17-3}{18}$$

Tangohia te 3 i te 17, ka 14.

$$x=\frac{14}{18}$$

Whakahekea te hautanga \frac{14}{18} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{7}{9}$$