Tīpoka ki ngā ihirangi matua
Whakaoti mō x
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Ngā Raru Ōrite mai i te Rapu Tukutuku

Tohaina

x+1=\frac{3}{6}
Whakawehea te 12 ki te 12, kia riro ko 1.
x+1=\frac{1}{2}
Whakahekea te hautanga \frac{3}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.
x=\frac{1}{2}-1
Tangohia te 1 mai i ngā taha e rua.
x=\frac{1}{2}-\frac{2}{2}
Me tahuri te 1 ki te hautau \frac{2}{2}.
x=\frac{1-2}{2}
Tā te mea he rite te tauraro o \frac{1}{2} me \frac{2}{2}, me tango rāua mā te tango i ō raua taurunga.
x=-\frac{1}{2}
Tangohia te 2 i te 1, ka -1.