Whakaoti i te x+1/3=17/6

$$x + \frac { 1 } { 3 } = \frac { 17 } { 6 }$$

Whakaoti mō x

$$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te \frac{1}{3} mai i ngā taha e rua.

$$x=\frac{17}{6}-\frac{1}{3}$$

Ko te maha noa iti rawa atu o 6 me 3 ko 6. Me tahuri \frac{17}{6} me \frac{1}{3} ki te hautau me te tautūnga 6.

$$x=\frac{17}{6}-\frac{2}{6}$$

Tā te mea he rite te tauraro o \frac{17}{6} me \frac{2}{6}, me tango rāua mā te tango i ō raua taurunga.

$$x=\frac{17-2}{6}$$

Tangohia te 2 i te 17, ka 15.

$$x=\frac{15}{6}$$

Whakahekea te hautanga \frac{15}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$x=\frac{5}{2}$$