Whakaoti i te v^2=9-10x

$$v ^ { 2 } = 9 - 10 x$$

Whakaoti mō x

$$x=\frac{9-v^{2}}{10}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$9-10x=v^{2}$$

Tangohia te 9 mai i ngā taha e rua.

$$-10x=v^{2}-9$$

Whakawehea ngā taha e rua ki te -10.

$$\frac{-10x}{-10}=\frac{v^{2}-9}{-10}$$

Mā te whakawehe ki te -10 ka wetekia te whakareanga ki te -10.

$$x=\frac{v^{2}-9}{-10}$$

Whakawehe v^{2}-9 ki te -10.

$$x=\frac{9-v^{2}}{10}$$

Whakaoti mō v (complex solution)

$$v=-\sqrt{9-10x}$$

$$v=\sqrt{9-10x}$$

Whakaoti mō v

$$v=\sqrt{9-10x}$$

$$v=-\sqrt{9-10x}\text{, }x\leq \frac{9}{10}$$