Whakaoti i te v^2=6

$$v ^ { 2 } = 6$$

Whakaoti mō v

$$v=\sqrt{6}\approx 2.449489743$$

$$v=-\sqrt{6}\approx -2.449489743$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$v=\sqrt{6} v=-\sqrt{6}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 6 mai i ngā taha e rua.

$$v^{2}-6=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -6 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$v=\frac{0±\sqrt{0^{2}-4\left(-6\right)}}{2}$$

Pūrua 0.

$$v=\frac{0±\sqrt{-4\left(-6\right)}}{2}$$

Whakareatia -4 ki te -6.

$$v=\frac{0±\sqrt{24}}{2}$$

Tuhia te pūtakerua o te 24.

$$v=\frac{0±2\sqrt{6}}{2}$$

Nā, me whakaoti te whārite v=\frac{0±2\sqrt{6}}{2} ina he tāpiri te ±.

$$v=\sqrt{6}$$

Nā, me whakaoti te whārite v=\frac{0±2\sqrt{6}}{2} ina he tango te ±.

$$v=-\sqrt{6}$$

Kua oti te whārite te whakatau.

$$v=\sqrt{6} v=-\sqrt{6}$$