Whakaoti i te v=sqrt{r/16}

$$v = \sqrt { \frac { r } { 16 } }$$

Whakaoti mō r

$$r=16v^{2}$$

$$v\geq 0$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{\frac{r}{16}}=v$$

Pūruatia ngā taha e rua o te whārite.

$$\frac{1}{16}r=v^{2}$$

Me whakarea ngā taha e rua ki te 16.

$$\frac{\frac{1}{16}r}{\frac{1}{16}}=\frac{v^{2}}{\frac{1}{16}}$$

Mā te whakawehe ki te \frac{1}{16} ka wetekia te whakareanga ki te \frac{1}{16}.

$$r=\frac{v^{2}}{\frac{1}{16}}$$

Whakawehe v^{2} ki te \frac{1}{16} mā te whakarea v^{2} ki te tau huripoki o \frac{1}{16}.

$$r=16v^{2}$$

Whakaoti mō r (complex solution)

$$r=16v^{2}$$

$$arg(v)<\pi \text{ or }v=0$$

Whakaoti mō v (complex solution)

$$v=\frac{\sqrt{r}}{4}$$

Whakaoti mō v

$$v=\frac{\sqrt{r}}{4}$$

$$r\geq 0$$