Whakaoti i te u-u-1/3=u-1-u/2

$$u- \frac{ u-1 }{ 3 } = u- \frac{ 1-u }{ 2 }$$

Whakaoti mō u

$$u=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 3,2.

$$6u-2\left(u-1\right)=6u-3\left(1-u\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te u-1.

$$6u-2u+2=6u-3\left(1-u\right)$$

Pahekotia te 6u me -2u, ka 4u.

$$4u+2=6u-3\left(1-u\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 1-u.

$$4u+2=6u-3+3u$$

Pahekotia te 6u me 3u, ka 9u.

$$4u+2=9u-3$$

Tangohia te 9u mai i ngā taha e rua.

$$4u+2-9u=-3$$

Pahekotia te 4u me -9u, ka -5u.

$$-5u+2=-3$$

Tangohia te 2 mai i ngā taha e rua.

$$-5u=-3-2$$

Tangohia te 2 i te -3, ka -5.

$$-5u=-5$$

Whakawehea ngā taha e rua ki te -5.

$$u=\frac{-5}{-5}$$

Whakawehea te -5 ki te -5, kia riro ko 1.

$$u=1$$