Whakaoti i te t^2-25=0

$$t ^ { 2 } - 25 = 0$$

Whakaoti mō t

$$t=5$$

$$t=-5$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Whakaarohia te t^{2}-25. Tuhia anō te t^{2}-25 hei t^{2}-5^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(t-5\right)\left(t+5\right)=0$$

Hei kimi otinga whārite, me whakaoti te t-5=0 me te t+5=0.

$$t=5 t=-5$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 25 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$t^{2}=25$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$t=5 t=-5$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$t^{2}-25=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -25 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$t=\frac{0±\sqrt{0^{2}-4\left(-25\right)}}{2}$$

Pūrua 0.

$$t=\frac{0±\sqrt{-4\left(-25\right)}}{2}$$

Whakareatia -4 ki te -25.

$$t=\frac{0±\sqrt{100}}{2}$$

Tuhia te pūtakerua o te 100.

$$t=\frac{0±10}{2}$$

Nā, me whakaoti te whārite t=\frac{0±10}{2} ina he tāpiri te ±. Whakawehe 10 ki te 2.

$$t=5$$

Nā, me whakaoti te whārite t=\frac{0±10}{2} ina he tango te ±. Whakawehe -10 ki te 2.

$$t=-5$$

Kua oti te whārite te whakatau.

$$t=5 t=-5$$