Whakaoti i te t^2-sqrt{3}c-6=0

$$t ^ { 2 } - \sqrt { 3 } c - 6 = 0$$

Whakaoti mō c

$$c=\frac{\sqrt{3}\left(t^{2}-6\right)}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te 6 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$t^{2}-\sqrt{3}c=6$$

Tangohia te t^{2} mai i ngā taha e rua.

$$-\sqrt{3}c=6-t^{2}$$

He hanga arowhānui tō te whārite.

$$\left(-\sqrt{3}\right)c=6-t^{2}$$

Whakawehea ngā taha e rua ki te -\sqrt{3}.

$$\frac{\left(-\sqrt{3}\right)c}{-\sqrt{3}}=\frac{6-t^{2}}{-\sqrt{3}}$$

Mā te whakawehe ki te -\sqrt{3} ka wetekia te whakareanga ki te -\sqrt{3}.

$$c=\frac{6-t^{2}}{-\sqrt{3}}$$

Whakawehe 6-t^{2} ki te -\sqrt{3}.

$$c=\frac{\sqrt{3}t^{2}}{3}-2\sqrt{3}$$

Whakaoti mō t

$$t=\sqrt{\sqrt{3}c+6}$$

$$t=-\sqrt{\sqrt{3}c+6}\text{, }c\geq -2\sqrt{3}$$