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t^{2}+6t-7.2=0
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
t=\frac{-6±\sqrt{6^{2}-4\left(-7.2\right)}}{2}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 6 mō b, me -7.2 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{-6±\sqrt{36-4\left(-7.2\right)}}{2}
Pūrua 6.
t=\frac{-6±\sqrt{36+28.8}}{2}
Whakareatia -4 ki te -7.2.
t=\frac{-6±\sqrt{64.8}}{2}
Tāpiri 36 ki te 28.8.
t=\frac{-6±\frac{18\sqrt{5}}{5}}{2}
Tuhia te pūtakerua o te 64.8.
t=\frac{\frac{18\sqrt{5}}{5}-6}{2}
Nā, me whakaoti te whārite t=\frac{-6±\frac{18\sqrt{5}}{5}}{2} ina he tāpiri te ±. Tāpiri -6 ki te \frac{18\sqrt{5}}{5}.
t=\frac{9\sqrt{5}}{5}-3
Whakawehe -6+\frac{18\sqrt{5}}{5} ki te 2.
t=\frac{-\frac{18\sqrt{5}}{5}-6}{2}
Nā, me whakaoti te whārite t=\frac{-6±\frac{18\sqrt{5}}{5}}{2} ina he tango te ±. Tango \frac{18\sqrt{5}}{5} mai i -6.
t=-\frac{9\sqrt{5}}{5}-3
Whakawehe -6-\frac{18\sqrt{5}}{5} ki te 2.
t=\frac{9\sqrt{5}}{5}-3 t=-\frac{9\sqrt{5}}{5}-3
Kua oti te whārite te whakatau.
t^{2}+6t-7.2=0
Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.
t^{2}+6t-7.2-\left(-7.2\right)=-\left(-7.2\right)
Me tāpiri 7.2 ki ngā taha e rua o te whārite.
t^{2}+6t=-\left(-7.2\right)
Mā te tango i te -7.2 i a ia ake anō ka toe ko te 0.
t^{2}+6t=7.2
Tango -7.2 mai i 0.
t^{2}+6t+3^{2}=7.2+3^{2}
Whakawehea te 6, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te 3. Nā, tāpiria te pūrua o te 3 ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.
t^{2}+6t+9=7.2+9
Pūrua 3.
t^{2}+6t+9=16.2
Tāpiri 7.2 ki te 9.
\left(t+3\right)^{2}=16.2
Tauwehea t^{2}+6t+9. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(t+3\right)^{2}}=\sqrt{16.2}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
t+3=\frac{9\sqrt{5}}{5} t+3=-\frac{9\sqrt{5}}{5}
Whakarūnātia.
t=\frac{9\sqrt{5}}{5}-3 t=-\frac{9\sqrt{5}}{5}-3
Me tango 3 mai i ngā taha e rua o te whārite.