Whakaoti mō t
t=\frac{1}{2}=0.5
Tautapa t
t≔\frac{1}{2}
Pātaitai
Trigonometry
5 raruraru e ōrite ana ki:
t = \sin ( 2 \frac { \pi } { 4 } - \frac { \pi } { 3 } )
Tohaina
Kua tāruatia ki te papatopenga
t=\sin(\frac{\pi }{2}-\frac{\pi }{3})
Whakakorea atu te tauwehe pūnoa nui rawa 4 i roto i te 2 me te 4.
t=\sin(\frac{1}{6}\pi )
Pahekotia te \frac{\pi }{2} me -\frac{\pi }{3}, ka \frac{1}{6}\pi .
t=\frac{1}{2}
Tīkina te uara \sin(\frac{1}{6}\pi ) mai i te ripanga uara pākoki.
Ngā Tauira
whārite tapawhā
{ x } ^ { 2 } - 4 x - 5 = 0
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