Whakaoti i te s=1/2gt^2+v_{0}t,quadd

$$s = \frac { 1 } { 2 } g t ^ { 2 } + v _ { 0 } t , \quad d$$

Whakaoti mō g

$$\left\{\begin{matrix}g=-\frac{2\left(tv_{0}-s\right)}{t^{2}}\text{, }&t\neq 0\\g\in \mathrm{R}\text{, }&s=0\text{ and }t=0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{1}{2}gt^{2}+v_{0}t=s$$

Tangohia te v_{0}t mai i ngā taha e rua.

$$\frac{1}{2}gt^{2}=s-v_{0}t$$

He hanga arowhānui tō te whārite.

$$\frac{t^{2}}{2}g=s-tv_{0}$$

Whakawehea ngā taha e rua ki te \frac{1}{2}t^{2}.

$$\frac{2\times \frac{t^{2}}{2}g}{t^{2}}=\frac{2\left(s-tv_{0}\right)}{t^{2}}$$

Mā te whakawehe ki te \frac{1}{2}t^{2} ka wetekia te whakareanga ki te \frac{1}{2}t^{2}.

$$g=\frac{2\left(s-tv_{0}\right)}{t^{2}}$$

Whakaoti mō s

$$s=\frac{t\left(gt+2v_{0}\right)}{2}$$