Whakaoti i te ri(x)=7(2x+3)+5(x+2)(x-4)

$$r i ( x ) = 7 ( 2 x + 3 ) + 5 ( x + 2 ) ( x - 4 )$$

Whakaoti mō r

$$r=-5ix-4i+\frac{19i}{x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 7 ki te 2x+3.

$$rix=14x+21+5\left(x+2\right)\left(x-4\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te x+2.

$$rix=14x+21+\left(5x+10\right)\left(x-4\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 5x+10 ki te x-4 ka whakakotahi i ngā kupu rite.

$$rix=14x+21+5x^{2}-10x-40$$

Pahekotia te 14x me -10x, ka 4x.

$$rix=4x+21+5x^{2}-40$$

Tangohia te 40 i te 21, ka -19.

$$rix=4x-19+5x^{2}$$

He hanga arowhānui tō te whārite.

$$ixr=5x^{2}+4x-19$$

Whakawehea ngā taha e rua ki te ix.

$$\frac{ixr}{ix}=\frac{5x^{2}+4x-19}{ix}$$

Mā te whakawehe ki te ix ka wetekia te whakareanga ki te ix.

$$r=\frac{5x^{2}+4x-19}{ix}$$

Whakawehe 4x-19+5x^{2} ki te ix.

$$r=-5ix-4i+\frac{19i}{x}$$

Whakaoti mō x

$$x=-\frac{\sqrt{396-8ir-r^{2}}}{10}+\frac{ir}{10}-\frac{2}{5}$$

$$x=\frac{\sqrt{396-8ir-r^{2}}}{10}+\frac{ir}{10}-\frac{2}{5}$$