Whakaoti i te r^2=r^2-2r+5

$$r ^ { 2 } = r ^ { 2 } - 2 r + 5$$

Whakaoti mō r

$$r = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te r^{2} mai i ngā taha e rua.

$$r^{2}-r^{2}=-2r+5$$

Pahekotia te r^{2} me -r^{2}, ka 0.

$$0=-2r+5$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-2r+5=0$$

Tangohia te 5 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-2r=-5$$

Whakawehea ngā taha e rua ki te -2.

$$r=\frac{-5}{-2}$$

Ka taea te hautanga \frac{-5}{-2} te whakamāmā ki te \frac{5}{2} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$r=\frac{5}{2}$$