Whakaoti i te nx-x=(n+3)(n+2)

$$n x - x = ( n + 3 ) ( n + 2 )$$

Whakaoti mō x

$$x=\frac{\left(n+2\right)\left(n+3\right)}{n-1}$$

$$n\neq 1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te n+3 ki te n+2 ka whakakotahi i ngā kupu rite.

$$nx-x=n^{2}+5n+6$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(n-1\right)x=n^{2}+5n+6$$

Whakawehea ngā taha e rua ki te n-1.

$$\frac{\left(n-1\right)x}{n-1}=\frac{\left(n+2\right)\left(n+3\right)}{n-1}$$

Mā te whakawehe ki te n-1 ka wetekia te whakareanga ki te n-1.

$$x=\frac{\left(n+2\right)\left(n+3\right)}{n-1}$$

Whakaoti mō n (complex solution)

$$n=\frac{-\sqrt{x^{2}-14x+1}+x-5}{2}$$

$$n=\frac{\sqrt{x^{2}-14x+1}+x-5}{2}$$

Whakaoti mō n

$$n=\frac{-\sqrt{x^{2}-14x+1}+x-5}{2}$$

$$n=\frac{\sqrt{x^{2}-14x+1}+x-5}{2}\text{, }x\geq 4\sqrt{3}+7\text{ or }x\leq 7-4\sqrt{3}$$