Whakaoti i te n(3/4-1/2n-1/2n+2-3/4)

$$n ( \frac { 3 } { 4 } - \frac { 1 } { 2 n } - \frac { 1 } { 2 n + 2 } - \frac { 3 } { 4 } )$$

Aromātai

$$-\frac{2n+1}{2\left(n+1\right)}$$

Ngā Hipanga Rongoā Poto

Tangohia te \frac{3}{4} i te \frac{3}{4}, ka 0.

$$n\left(-\frac{1}{2n}-\frac{1}{2n+2}\right)$$

Tauwehea te 2n+2.

$$n\left(-\frac{1}{2n}-\frac{1}{2\left(n+1\right)}\right)$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 2n me 2\left(n+1\right) ko 2n\left(n+1\right). Whakareatia -\frac{1}{2n} ki te \frac{n+1}{n+1}. Whakareatia \frac{1}{2\left(n+1\right)} ki te \frac{n}{n}.

$$n\left(-\frac{n+1}{2n\left(n+1\right)}-\frac{n}{2n\left(n+1\right)}\right)$$

Tā te mea he rite te tauraro o -\frac{n+1}{2n\left(n+1\right)} me \frac{n}{2n\left(n+1\right)}, me tango rāua mā te tango i ō raua taurunga.

$$n\times \frac{-\left(n+1\right)-n}{2n\left(n+1\right)}$$

Mahia ngā whakarea i roto o -\left(n+1\right)-n.

$$n\times \frac{-n-1-n}{2n\left(n+1\right)}$$

Whakakotahitia ngā kupu rite i -n-1-n.

$$n\times \frac{-2n-1}{2n\left(n+1\right)}$$

Tuhia te n\times \frac{-2n-1}{2n\left(n+1\right)} hei hautanga kotahi.

$$\frac{n\left(-2n-1\right)}{2n\left(n+1\right)}$$

Me whakakore tahi te n i te taurunga me te tauraro.

$$\frac{-2n-1}{2\left(n+1\right)}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te n+1.

$$\frac{-2n-1}{2n+2}$$

Whakaroha

$$-\frac{2n+1}{2\left(n+1\right)}$$

Ngā Hipanga Rongoā Poto

Tangohia te \frac{3}{4} i te \frac{3}{4}, ka 0.

$$n\left(-\frac{1}{2n}-\frac{1}{2n+2}\right)$$

Tauwehea te 2n+2.

$$n\left(-\frac{1}{2n}-\frac{1}{2\left(n+1\right)}\right)$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 2n me 2\left(n+1\right) ko 2n\left(n+1\right). Whakareatia -\frac{1}{2n} ki te \frac{n+1}{n+1}. Whakareatia \frac{1}{2\left(n+1\right)} ki te \frac{n}{n}.

$$n\left(-\frac{n+1}{2n\left(n+1\right)}-\frac{n}{2n\left(n+1\right)}\right)$$

Tā te mea he rite te tauraro o -\frac{n+1}{2n\left(n+1\right)} me \frac{n}{2n\left(n+1\right)}, me tango rāua mā te tango i ō raua taurunga.

$$n\times \frac{-\left(n+1\right)-n}{2n\left(n+1\right)}$$

Mahia ngā whakarea i roto o -\left(n+1\right)-n.

$$n\times \frac{-n-1-n}{2n\left(n+1\right)}$$

Whakakotahitia ngā kupu rite i -n-1-n.

$$n\times \frac{-2n-1}{2n\left(n+1\right)}$$

Tuhia te n\times \frac{-2n-1}{2n\left(n+1\right)} hei hautanga kotahi.

$$\frac{n\left(-2n-1\right)}{2n\left(n+1\right)}$$

Me whakakore tahi te n i te taurunga me te tauraro.

$$\frac{-2n-1}{2\left(n+1\right)}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te n+1.

$$\frac{-2n-1}{2n+2}$$