Tauwehe
\frac{\left(2n-1\right)\left(4n^{2}+2n+1\right)}{8}
Aromātai
n^{3}-\frac{1}{8}
Tohaina
Kua tāruatia ki te papatopenga
\frac{8n^{3}-1}{8}
Tauwehea te \frac{1}{8}.
\left(2n-1\right)\left(4n^{2}+2n+1\right)
Whakaarohia te 8n^{3}-1. Tuhia anō te 8n^{3}-1 hei \left(2n\right)^{3}-1^{3}. Ka taea te rerekētanga o ngā pūtoru te whakatauwehe mā te whakamahi i te ture: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
\frac{\left(2n-1\right)\left(4n^{2}+2n+1\right)}{8}
Me tuhi anō te kīanga whakatauwehe katoa. Kāore te pūrau 4n^{2}+2n+1 i whakatauwehea i te mea kāhore ōna pūtake whakahau.
Ngā Tauira
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