Whakaoti i te n^2=17

$$n ^ { 2 } = 17$$

Whakaoti mō n

$$n=\sqrt{17}\approx 4.123105626$$

$$n=-\sqrt{17}\approx -4.123105626$$

Ngā Upane mā te Kimi Pūtakerua

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$n=\sqrt{17} n=-\sqrt{17}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 17 mai i ngā taha e rua.

$$n^{2}-17=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -17 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$n=\frac{0±\sqrt{0^{2}-4\left(-17\right)}}{2}$$

Pūrua 0.

$$n=\frac{0±\sqrt{-4\left(-17\right)}}{2}$$

Whakareatia -4 ki te -17.

$$n=\frac{0±\sqrt{68}}{2}$$

Tuhia te pūtakerua o te 68.

$$n=\frac{0±2\sqrt{17}}{2}$$

Nā, me whakaoti te whārite n=\frac{0±2\sqrt{17}}{2} ina he tāpiri te ±.

$$n=\sqrt{17}$$

Nā, me whakaoti te whārite n=\frac{0±2\sqrt{17}}{2} ina he tango te ±.

$$n=-\sqrt{17}$$

Kua oti te whārite te whakatau.

$$n=\sqrt{17} n=-\sqrt{17}$$