Whakaoti i te mx^2-2mx+4=0

$$m x ^ { 2 } - 2 m x + 4 = 0$$

Whakaoti mō m

$$m=-\frac{4}{x\left(x-2\right)}$$

$$x\neq 2\text{ and }x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 4 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$mx^{2}-2mx=-4$$

Pahekotia ngā kīanga tau katoa e whai ana i te m.

$$\left(x^{2}-2x\right)m=-4$$

Whakawehea ngā taha e rua ki te x^{2}-2x.

$$\frac{\left(x^{2}-2x\right)m}{x^{2}-2x}=-\frac{4}{x^{2}-2x}$$

Mā te whakawehe ki te x^{2}-2x ka wetekia te whakareanga ki te x^{2}-2x.

$$m=-\frac{4}{x^{2}-2x}$$

Whakawehe -4 ki te x^{2}-2x.

$$m=-\frac{4}{x\left(x-2\right)}$$

Whakaoti mō x (complex solution)

$$x=\frac{\sqrt{m\left(m-4\right)}+m}{m}$$

$$x=\frac{-\sqrt{m\left(m-4\right)}+m}{m}\text{, }m\neq 0$$

Whakaoti mō x

$$x=\frac{\sqrt{m\left(m-4\right)}+m}{m}$$

$$x=\frac{-\sqrt{m\left(m-4\right)}+m}{m}\text{, }m<0\text{ or }m\geq 4$$