Whakaoti i te mx^2+1=9-mx^2

$$m x ^ { 2 } + 1 = 9 - m x ^ { 2 }$$

Whakaoti mō m

$$m=\frac{4}{x^{2}}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te mx^{2} ki ngā taha e rua.

$$mx^{2}+1+mx^{2}=9$$

Pahekotia te mx^{2} me mx^{2}, ka 2mx^{2}.

$$2mx^{2}+1=9$$

Tangohia te 1 mai i ngā taha e rua.

$$2mx^{2}=9-1$$

Tangohia te 1 i te 9, ka 8.

$$2mx^{2}=8$$

He hanga arowhānui tō te whārite.

$$2x^{2}m=8$$

Whakawehea ngā taha e rua ki te 2x^{2}.

$$\frac{2x^{2}m}{2x^{2}}=\frac{8}{2x^{2}}$$

Mā te whakawehe ki te 2x^{2} ka wetekia te whakareanga ki te 2x^{2}.

$$m=\frac{8}{2x^{2}}$$

Whakawehe 8 ki te 2x^{2}.

$$m=\frac{4}{x^{2}}$$

Whakaoti mō x (complex solution)

$$x=-2m^{-\frac{1}{2}}$$

$$x=2m^{-\frac{1}{2}}\text{, }m\neq 0$$

Whakaoti mō x

$$x=\frac{2}{\sqrt{m}}$$

$$x=-\frac{2}{\sqrt{m}}\text{, }m>0$$