Whakaoti mō m
m=-\frac{4-x}{x\left(x+7\right)}
x\neq -7\text{ and }x\neq 0\text{ and }x\neq 2
Whakaoti mō x
\left\{\begin{matrix}x=\frac{-\sqrt{49m^{2}-30m+1}-7m+1}{2m}\text{, }&\left(m\neq -\frac{1}{9}\text{ and }m\neq 0\text{ and }m\leq \frac{15-4\sqrt{11}}{49}\right)\text{ or }m\geq \frac{4\sqrt{11}+15}{49}\\x=\frac{\sqrt{49m^{2}-30m+1}-7m+1}{2m}\text{, }&\left(m\neq 0\text{ and }m\leq \frac{15-4\sqrt{11}}{49}\right)\text{ or }m\geq \frac{4\sqrt{11}+15}{49}\\x=4\text{, }&m=0\end{matrix}\right.
Graph
Tohaina
Kua tāruatia ki te papatopenga
mx\left(x-2\right)\left(x+7\right)=x^{2}-6x+8
Whakareatia ngā taha e rua o te whārite ki te \left(x-2\right)\left(x+7\right).
\left(mx^{2}-2mx\right)\left(x+7\right)=x^{2}-6x+8
Whakamahia te āhuatanga tohatoha hei whakarea te mx ki te x-2.
mx^{3}+5mx^{2}-14mx=x^{2}-6x+8
Whakamahia te āhuatanga tuaritanga hei whakarea te mx^{2}-2mx ki te x+7 ka whakakotahi i ngā kupu rite.
\left(x^{3}+5x^{2}-14x\right)m=x^{2}-6x+8
Pahekotia ngā kīanga tau katoa e whai ana i te m.
\frac{\left(x^{3}+5x^{2}-14x\right)m}{x^{3}+5x^{2}-14x}=\frac{\left(x-4\right)\left(x-2\right)}{x^{3}+5x^{2}-14x}
Whakawehea ngā taha e rua ki te x^{3}+5x^{2}-14x.
m=\frac{\left(x-4\right)\left(x-2\right)}{x^{3}+5x^{2}-14x}
Mā te whakawehe ki te x^{3}+5x^{2}-14x ka wetekia te whakareanga ki te x^{3}+5x^{2}-14x.
m=\frac{x-4}{x\left(x+7\right)}
Whakawehe \left(-4+x\right)\left(-2+x\right) ki te x^{3}+5x^{2}-14x.
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