Whakaoti i te m(2x-3)/5+(4x-1)/10=1

$$m \frac { ( 2 x - 3 ) } { 5 } + \frac { ( 4 x - 1 ) } { 10 } = 1$$

Whakaoti mō m

$$m=-\frac{4x-11}{2\left(2x-3\right)}$$

$$x\neq \frac{3}{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 10, arā, te tauraro pātahi he tino iti rawa te kitea o 5,10.

$$2m\left(2x-3\right)+4x-1=10$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2m ki te 2x-3.

$$4mx-6m+4x-1=10$$

Tangohia te 4x mai i ngā taha e rua.

$$4mx-6m-1=10-4x$$

Me tāpiri te 1 ki ngā taha e rua.

$$4mx-6m=10-4x+1$$

Tāpirihia te 10 ki te 1, ka 11.

$$4mx-6m=11-4x$$

Pahekotia ngā kīanga tau katoa e whai ana i te m.

$$\left(4x-6\right)m=11-4x$$

Whakawehea ngā taha e rua ki te 4x-6.

$$\frac{\left(4x-6\right)m}{4x-6}=\frac{11-4x}{4x-6}$$

Mā te whakawehe ki te 4x-6 ka wetekia te whakareanga ki te 4x-6.

$$m=\frac{11-4x}{4x-6}$$

Whakawehe 11-4x ki te 4x-6.

$$m=\frac{11-4x}{2\left(2x-3\right)}$$

Whakaoti mō x

$$x=\frac{6m+11}{4\left(m+1\right)}$$

$$m\neq -1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 10, arā, te tauraro pātahi he tino iti rawa te kitea o 5,10.

$$2m\left(2x-3\right)+4x-1=10$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2m ki te 2x-3.

$$4xm-6m+4x-1=10$$

Me tāpiri te 6m ki ngā taha e rua.

$$4xm+4x-1=10+6m$$

Me tāpiri te 1 ki ngā taha e rua.

$$4xm+4x=10+6m+1$$

Tāpirihia te 10 ki te 1, ka 11.

$$4xm+4x=11+6m$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(4m+4\right)x=11+6m$$

He hanga arowhānui tō te whārite.

$$\left(4m+4\right)x=6m+11$$

Whakawehea ngā taha e rua ki te 4m+4.

$$\frac{\left(4m+4\right)x}{4m+4}=\frac{6m+11}{4m+4}$$

Mā te whakawehe ki te 4m+4 ka wetekia te whakareanga ki te 4m+4.

$$x=\frac{6m+11}{4m+4}$$

Whakawehe 11+6m ki te 4m+4.

$$x=\frac{6m+11}{4\left(m+1\right)}$$