Whakaoti i te m^2-3m

$$m ^ { 2 } - 3 m$$

Tauwehe

$$m\left(m-3\right)$$

Ngā Upane Otinga

Tauwehea te m.

$$m\left(m-3\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$m^{2}-3m=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$m=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}}}{2}$$

Tuhia te pūtakerua o te \left(-3\right)^{2}.

$$m=\frac{-\left(-3\right)±3}{2}$$

Ko te tauaro o -3 ko 3.

$$m=\frac{3±3}{2}$$

Nā, me whakaoti te whārite m=\frac{3±3}{2} ina he tāpiri te ±. Tāpiri 3 ki te 3.

$$m=\frac{6}{2}$$

Whakawehe 6 ki te 2.

$$m=3$$

Nā, me whakaoti te whārite m=\frac{3±3}{2} ina he tango te ±. Tango 3 mai i 3.

$$m=\frac{0}{2}$$

Whakawehe 0 ki te 2.

$$m=0$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 3 mō te x_{1} me te 0 mō te x_{2}.

$$m^{2}-3m=\left(m-3\right)m$$

Aromātai

$$m\left(m-3\right)$$