Whakaoti i te m:(-1/2)^3*sqrt{25/4}*sqrt{(8/3)^2}=3^-1

$$m : ( - \frac { 1 } { 2 } ) ^ { 3 } \times \sqrt { \frac { 25 } { 4 } } \times \sqrt { ( \frac { 8 } { 3 } ) ^ { 2 } } = 3 ^ { - 1 }$$

Whakaoti mō m

$$m=-\frac{1}{160}=-0.00625$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te -\frac{1}{2} mā te pū o 3, kia riro ko -\frac{1}{8}.

$$\frac{m}{-\frac{1}{8}}\sqrt{\frac{25}{4}}\sqrt{\left(\frac{8}{3}\right)^{2}}=3^{-1}$$

Tuhia anō te pūtake rua o te whakawehenga \frac{25}{4} hei whakawehenga o ngā pūtake rua \frac{\sqrt{25}}{\sqrt{4}}. Tuhia te pūtakerua o te taurunga me te tauraro.

$$\frac{m}{-\frac{1}{8}}\times \frac{5}{2}\sqrt{\left(\frac{8}{3}\right)^{2}}=3^{-1}$$

Tātaihia te \frac{8}{3} mā te pū o 2, kia riro ko \frac{64}{9}.

$$\frac{m}{-\frac{1}{8}}\times \frac{5}{2}\sqrt{\frac{64}{9}}=3^{-1}$$

Tuhia anō te pūtake rua o te whakawehenga \frac{64}{9} hei whakawehenga o ngā pūtake rua \frac{\sqrt{64}}{\sqrt{9}}. Tuhia te pūtakerua o te taurunga me te tauraro.

$$\frac{m}{-\frac{1}{8}}\times \frac{5}{2}\times \frac{8}{3}=3^{-1}$$

Whakareatia te \frac{5}{2} ki te \frac{8}{3}, ka \frac{20}{3}.

$$\frac{m}{-\frac{1}{8}}\times \frac{20}{3}=3^{-1}$$

Tātaihia te 3 mā te pū o -1, kia riro ko \frac{1}{3}.

$$\frac{m}{-\frac{1}{8}}\times \frac{20}{3}=\frac{1}{3}$$

Me whakarea ngā taha e rua ki te \frac{3}{20}, te tau utu o \frac{20}{3}.

$$\frac{m}{-\frac{1}{8}}=\frac{1}{3}\times \frac{3}{20}$$

Whakareatia te \frac{1}{3} ki te \frac{3}{20}, ka \frac{1}{20}.

$$\frac{m}{-\frac{1}{8}}=\frac{1}{20}$$

Me whakarea ngā taha e rua ki te -\frac{1}{8}.

$$m=\frac{1}{20}\left(-\frac{1}{8}\right)$$

Whakareatia te \frac{1}{20} ki te -\frac{1}{8}, ka -\frac{1}{160}.

$$m=-\frac{1}{160}$$