Whakaoti i te m/1/8=4/3x+1

$$m / \frac { 1 } { 8 } = \frac { 4 } { 3 x } + 1$$

Whakaoti mō m

$$m=\frac{1}{8}+\frac{1}{6x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

He hanga arowhānui tō te whārite.

$$8m=1+\frac{4}{3x}$$

Whakawehea ngā taha e rua ki te 8.

$$\frac{8m}{8}=\frac{1+\frac{4}{3x}}{8}$$

Mā te whakawehe ki te 8 ka wetekia te whakareanga ki te 8.

$$m=\frac{1+\frac{4}{3x}}{8}$$

Whakawehe 1+\frac{4}{3x} ki te 8.

$$m=\frac{1}{8}+\frac{1}{6x}$$

Whakaoti mō x

$$x=-\frac{4}{3\left(1-8m\right)}$$

$$m\neq \frac{1}{8}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te 3x.

$$3x\times \frac{m}{\frac{1}{8}}=4+3x$$

Tangohia te 3x mai i ngā taha e rua.

$$3x\times \frac{m}{\frac{1}{8}}-3x=4$$

Pahekotia ngā kīanga tau katoa e whai ana i te x.

$$\left(3\times \frac{m}{\frac{1}{8}}-3\right)x=4$$

He hanga arowhānui tō te whārite.

$$\left(24m-3\right)x=4$$

Whakawehea ngā taha e rua ki te 24m-3.

$$\frac{\left(24m-3\right)x}{24m-3}=\frac{4}{24m-3}$$

Mā te whakawehe ki te 24m-3 ka wetekia te whakareanga ki te 24m-3.

$$x=\frac{4}{24m-3}$$

Whakawehe 4 ki te 24m-3.

$$x=\frac{4}{3\left(8m-1\right)}$$

Tē taea kia ōrite te tāupe x ki 0.

$$x=\frac{4}{3\left(8m-1\right)}\text{, }x\neq 0$$