Whakaoti i te k=deltak+28

$$k = \delta k+28$$

Whakaoti mō k

$$k=\frac{28}{1-\delta }$$

$$\delta \neq 1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te \delta k mai i ngā taha e rua.

$$k-\delta k=28$$

Pahekotia ngā kīanga tau katoa e whai ana i te k.

$$\left(1-\delta \right)k=28$$

Whakawehea ngā taha e rua ki te -\delta +1.

$$\frac{\left(1-\delta \right)k}{1-\delta }=\frac{28}{1-\delta }$$

Mā te whakawehe ki te -\delta +1 ka wetekia te whakareanga ki te -\delta +1.

$$k=\frac{28}{1-\delta }$$

Whakaoti mō δ

$$\delta =\frac{k-28}{k}$$

$$k\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\delta k+28=k$$

Tangohia te 28 mai i ngā taha e rua.

$$\delta k=k-28$$

He hanga arowhānui tō te whārite.

$$k\delta =k-28$$

Whakawehea ngā taha e rua ki te k.

$$\frac{k\delta }{k}=\frac{k-28}{k}$$

Mā te whakawehe ki te k ka wetekia te whakareanga ki te k.

$$\delta =\frac{k-28}{k}$$