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Kimi Pārōnaki e ai ki x
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2\left(-\frac{1}{3}\right)x^{2-1}
Ko te pārōnaki o ax^{n} ko nax^{n-1}.
-\frac{2}{3}x^{2-1}
Whakareatia 2 ki te -\frac{1}{3}.
-\frac{2}{3}x^{1}
Tango 1 mai i 2.
-\frac{2}{3}x
Mō tētahi kupu t, t^{1}=t.